In serial dilution if folded 2 tube the dilute in number 6 is:
- A- 1/32
- B- 1/64
- C- 1/128
- D- 1/256.
In serial dilution, if you fold 2 tubes, the dilution in number 6 is: 1/256.
Here's how we can arrive at the answer:
- Starting Concentration:
We typically begin with a concentration of 1.
- Folding:
Each time you fold the dilution, you essentially double the dilution factor. In this case, folding 2 tubes means the dilution factor is multiplied by 2 twice.
- Dilution Factor:
Therefore, the dilution factor for 6 folds would be 2 ^ 6 = 64.
- Final Concentration:
The final concentration in each tube is obtained by dividing the initial concentration by the dilution factor. So, for tube number 6, the concentration would be 1 / 64 = 1/256.
Therefore, option D (1/256) is the correct answer.
